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26=6+37x-16x^2
We move all terms to the left:
26-(6+37x-16x^2)=0
We get rid of parentheses
16x^2-37x-6+26=0
We add all the numbers together, and all the variables
16x^2-37x+20=0
a = 16; b = -37; c = +20;
Δ = b2-4ac
Δ = -372-4·16·20
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-\sqrt{89}}{2*16}=\frac{37-\sqrt{89}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+\sqrt{89}}{2*16}=\frac{37+\sqrt{89}}{32} $
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